15x^2+62x-72=0

Solution for 15x^2+62x-72=0 equation:

15x^2+62x-72=0

a = 15; b = 62; c = -72;
Δ = b2-4ac
Δ = 622-4·15·(-72)
Δ = 8164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8164}=\sqrt{4*2041}=\sqrt{4}*\sqrt{2041}=2\sqrt{2041}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{2041}}{2*15}=\frac{-62-2\sqrt{2041}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{2041}}{2*15}=\frac{-62+2\sqrt{2041}}{30}
$